Meeting rooms ii java.
As soon as the current meeting is finished the room can be used for another.
The next video is starting stop.
If you have a facebook interview this question is a must know.
There are n meetings in the form of s i f i where s i is the start time of meeting i and f i is finish time of meeting i the task is to find the maximum number of meetings that can be accommodated in the meeting room.
When we see the second meeting we check if its start time is later than the first meeting s end time.
Leetcode 253 meeting rooms ii.
For example given 0 30 5 10 15 20 return false.
Suppose we have three meetings.
Meeting rooms ii given an array of meeting time intervals consisting of start and end times s1 e1 s2 e2 si ei find the minimum number of conference rooms required.
There is one meeting room in a firm.
Given an array of meeting time intervals consisting of start and end times s1 e1 s2 e2 si ei determine if a person could attend all meetings.
0 30 5 10 and 15 20 in sorted order.
Meeting rooms ii given an array of meeting time intervals consisting of start and end times s1 e1 s2 e2 si ei find the minimum number of conference rooms required for example.
Given an array of meeting time intervals consisting of start and end times s1 e1 s2 e2 find the minimum number of conference rooms required.
Facebook s 3rd most commonly asked question.
Java solution when a room is taken the room can not be used for anther meeting until the current meeting is over.
It s not so we need another room.